RegEx: Grabbing text between quotation marks for selective switch

Question

If there is a String like this:

HYPERLINK "hyperlink_funda.docx" \l "FunHere" \o "text" \t "_parent"

What regex could return the value enclosed in quotation mark only for switch \l?

FunHere

People should suggest the reason if they down vote. I don't see any thing incorrect in getting the regex for the scenario in question. — unknown_boundaries, Sep 12 '14 at 11:15
i'm not the downvoter , downvote is because of there are large number of questions like this on SO. A simple searching will give you the exact regex. And also you need to show your attempts. — Avinash Raj, Sep 12 '14 at 11:19
Thanks for suggestion. I could not find any with selective selection. Please add link if you're seeing any. — unknown_boundaries, Sep 12 '14 at 11:21

score 3 · Accepted Answer · answered Sep 12 '14 at 11:06

3

Assuming there's no escaped " or lines in // comments that should be accounted for:

\\l\s*"([^"]*)

Regular expression visualization

Debuggex Demo Your match will be in group 1.

answered Sep 12 '14 at 11:06

asontu

score 1 · Answer 2 · answered Sep 12 '14 at 11:11

1

The following regex will capture the required words in the 1st capture group:

\\l\s*"(\w+)"

answered Sep 12 '14 at 11:11

hehe

2 Answers2