How Java If statements work when having && AND ||

Question

If you write this in an if statement (this is an example):

if (A == 1 && B == 1
||
C == 1 && D == 1)

Does Java think like this: if A and B is equal to 1 OR C == 1 and D == 1, then it's true. Or does Java think: if A and B or C is equal to 1 AND D is equal to 1, then it's true. And there's more possibilities with AND and OR..

This is a problem in my programming because I'm not sure about this question.

/Viktor

operator== has an higher priority than operator&&, which has an highe r precedence than operator|| — nbro, Sep 13 '14 at 15:51

score 2 · Accepted Answer · edited Sep 13 '14 at 15:57

2

&& has a higher precedence than ||, so it is interpreted first. i.e., it's equivalent of

if ((A == 1 && B == 1)
    ||
    (C == 1 && D == 1))

edited Sep 13 '14 at 15:57

Martin Smith

438,706
87
741
845

answered Sep 13 '14 at 15:51

Mureinik

297,002
52
306
350

score 1 · Answer 2 · answered Sep 13 '14 at 15:55

Comparison operator == has an higher priority than the AND logical operator &&, which has an higher precedence than the OR logical operator ||. See documentation for more information: http://docs.oracle.com/javase/tutorial/java/nutsandbolts/operators.html

In general, if you are not sure about the operators priority, use brackets.

How Java If statements work when having && AND ||

2 Answers2