How is a default move constructor for a class with STL members defined?

Asked Sep 15 '14 at 12:31

Active Sep 15 '14 at 12:34

Viewed 82 times

I have searched this a little bit but couldn't find a similar example so I wanted to ask just to be sure. If I have a class with no explicit heap allocation but only STL classes like so:

class Klass {
..
private:
  vector<int> v;
};

Does default move constructor provide me the proper move semantics for free, that is something similar to Klass(Klass&& other) : v(move(other.v)) { .. }?

edited Sep 15 '14 at 12:34

Niall

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asked Sep 15 '14 at 12:31

none

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You may find this question useful: [Does a =default move constructor equals to a member-wise move constructor?](http://stackoverflow.com/q/18290523/1708801) – Shafik Yaghmour Sep 15 '14 at 12:32
Yep, that's a duplicate – Marco A. Sep 15 '14 at 12:34
@ShafikYaghmour indeed I did, thanks.. – none Sep 15 '14 at 12:35
Table of generated special members: http://stackoverflow.com/a/24512883/3747990 – Niall Sep 15 '14 at 12:37

How is a default move constructor for a class with STL members defined?

0 Answers0