How to build dictionary from two lists

Question

With two lists of different sizes:

numbers=[1,2,3,4,5]
cities=['LA','NY','SF']

I need to get this:

result={1:'LA', 2:'NY', 3:'SF'}

I thought of doing it with:

result={number:cities[numbers.index(number)] for number in numbers if numbers.index(number)<len(cities)}

But this one-liner gets kind of long. I wonder if there is an alternative way of achieving the same goal.

EDITED LATER:

There were multiple suggestions made to use zip:

dict(zip(cities, numbers))

While it is a definitely a simpler syntax than list comprehension I've used I wonder which would be faster to execute?

score 3 · Accepted Answer · answered Sep 18 '14 at 20:03

3

Use zip, it will only zip upto the end of the shortest sequence

dict(zip(cities, numbers))

answered Sep 18 '14 at 20:03

b10n

score 1 · Answer 2 · answered Sep 18 '14 at 20:04

1

numbers=[1,2,3,4,5]
cities=['LA','NY','SF']
dict(zip(cities,numbers))

;)

I suspect it is duplicate though - search before you post

answered Sep 18 '14 at 20:04

user1941126

If its a duplicate "they" are usually quick on letting know it is! – alphanumeric Sep 18 '14 at 20:05

score 1 · Answer 3 · answered Sep 18 '14 at 20:04

1

The easiest is probably dict(zip(numbers,cities)) zip will stop once any of the lists ends, which is what you want.

answered Sep 18 '14 at 20:04

ilmarinen