Strpos from variable

Asked Sep 19 '14 at 12:35

Active Sep 19 '14 at 13:38

Viewed 33 times

The following code prints an array of values where whatever is written in MySearchField is found in the values of $FullLinks:

<?
function myFilter($string) {
return strpos($string,'MySearchField') !== false;
}

$newArray = array_filter($FullLinks, 'myFilter');
?>

<pre> <? print_r($newArray); ?> </pre>

However, if I use a variable instead then it won't show any values. For example:

return strpos($string,$MySearchField) !== false;

Can anyone tell me how I can get the search word from a variable instead?

Any actual answers would be really appreciated. I have no idea how to use the variable scope article posted.

edited Sep 19 '14 at 13:38

asked Sep 19 '14 at 12:35

user2803146

How do you define `$MySearchField`? post the complete function – Gerald Schneider Sep 19 '14 at 12:37
A simple scope issue, see the duplicate. The best solution is probably `array_filter($fullLinks, function ($string) use ($MySearchField) { return strpos(...); })` – deceze Sep 19 '14 at 12:38
@GeraldSchneider $MySearchField= 'MyText'; – user2803146 Sep 19 '14 at 13:35
@deceze How would I implement that code? – user2803146 Sep 19 '14 at 13:39
1

Basically exactly as I've shown. `$newArray = array_filter($fullLinks, function ($string) use ($MySearchField) { return strpos($string, $MySearchField) !== false; });` – deceze Sep 19 '14 at 13:44
@deceze I get: Warning: array_filter() expects parameter 1 to be array – user2803146 Sep 19 '14 at 13:51
Maybe I typo'd the variable or you did. Check that `$fullLinks` is correct. – deceze Sep 19 '14 at 13:58
@deceze Thanks matey, that works. Dreamweaver is throwing me a syntax error but its working fine in my browser. Thank you. – user2803146 Sep 19 '14 at 17:16

Strpos from variable

0 Answers0