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I am trying to convert a String number to two decimal places in Java. I saw lot of posts on satckoverflow but somehow I am getting an exception.

String number = "1.9040409535344458";
String result = String.format("%.2f", number);

System.out.println(result);

This is the exception I am getting - 

java.util.IllegalFormatConversionException: f != java.lang.String

I would like to have 1.904 as the output. Does anyone know what wrong I am doing here?

Community
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john
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  • Your number variable is String instead double or float. – Petar Butkovic Sep 20 '14 at 19:43
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    Convert the string to a number and then use the format. – Henry Sep 20 '14 at 19:43
  • I did that also `String.format("%.2f", Integer.parseInt(number));` and this time I am getting an exception as `java.lang.NumberFormatException: For input string: "1.9040409535344458"` – john Sep 20 '14 at 19:44
  • Because number is not an integer, but a float/double Edit: you should use `Double.parseDouble(number)` instead. – Kulu Limpa Sep 20 '14 at 19:45

4 Answers4

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You can try using a NumberFormat. For example:

String number = "1.9040409535344458";
NumberFormat formatter = new DecimalFormat("#0.000"); 
String result = formatter.format(Double.valueOf(number));

System.out.println(result);
Konstantin Yovkov
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Just declare number to be double : 

Double number = 1.9040409535344458;

instead of 

String number = "1.9040409535344458";

OUTPUT : 

1.90
afzalex
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You are using a format not meant for a String. I would recommend either converting your String to a double or storing it as a double in the first place. Convert the String to a double, and pass that double to String.format.

J0e3gan
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Armek
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you should first convert the string into double and then change the decimal value

String number = "1.9040409535344458";
double result = Double.parseDouble(number);//converts the string into double
result = result *100;//adjust the decimal value
System.out.println(result);
Abhishek Chawla
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