Regular expression to find exact part in a string using php

Question

What should I use as a regex in order to get just the text between the double qoutes after url=

  <div class="anc-style" 
       url="c2l0ZT1odHRwJTNBJTJGJTJGZWFzeXJvdGF0b3IuY29tJTJGNjE1OTYlMkYmc2VjP TE1MjIzMyZsZW5nPWV4dGUmYWQ9MmM5ZTE5YjhiZWRiNzI1N2MxZGU2ODA2 Mjk0ZGZiYzcmYWQyPTAmYWQzPTAmYWQ0PTM=">

[**DO NOT PARSE XML WITH REGEX.**](http://stackoverflow.com/a/1732454/510036). Seriously. — Qix - MONICA WAS MISTREATED, Sep 21 '14 at 19:31

Nomad · Accepted Answer · 2014-09-22T01:42:04.890

0

You regexp would be

$string = "your string here";

echo urldecode(base64_decode(preg_replace('/^.*url="(.*)".*$/', '$1', $string)));

If that's the url you want, I added base64_decode, and then urldecode since the result contained urlencoded characters.

Also I stongly suggest you learn regex basics if you'll be needing other search and replace!

edited Sep 22 '14 at 01:42

answered Sep 21 '14 at 19:43

Nomad

58
8

my point was how to get the exact url(c2l0ZT1odHRwJTNBJTJGJTJGZWFzeXJvdGF0b3IuY29tJTJGNjE1OTYlMkYmc2VjP TE1MjIzMyZsZW5nPWV4dGUmYWQ9MmM5ZTE5YjhiZWRiNzI1N2MxZGU2ODA2 Mjk0ZGZiYzcmYWQyPTAmYWQzPTAmYWQ0PTM=) from html document that contains this url – demonlesna Sep 21 '14 at 21:09

Regular expression to find exact part in a string using php

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