How do I extract a substring from a string until the second space is encountered?

Question

I have a string like this:

"o1 1232.5467 1232.5467 1232.5467 1232.5467 1232.5467 1232.5467"

How do I extract only "o1 1232.5467"?

The number of characters to be extracted are not the same always. Hence, I want to only extract until the second space is encountered.

Will there always be just 1 space between words? If not, most of the solutions below are invalid. — Francisco Noriega, Apr 08 '10 at 17:44

score 65 · Answer 1 · edited Jan 11 '15 at 00:05

65

A straightforward approach would be the following:

string[] tokens = str.Split(' ');
string retVal = tokens[0] + " " + tokens[1];

edited Jan 11 '15 at 00:05

Pico Riley

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5

answered Apr 08 '10 at 12:26

Sorantis

14,496
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initially i liked this solution, but i wanna account for the possibility of there being zero spaces in the input string. in which case this solution would break, right? – sashn Nov 14 '22 at 16:07

score 28 · Answer 2 · answered Apr 08 '10 at 12:26

28

Just use String.IndexOf twice as in:

     string str = "My Test String";
     int index = str.IndexOf(' ');
     index = str.IndexOf(' ', index + 1);
     string result = str.Substring(0, index);

answered Apr 08 '10 at 12:26

Hans Olsson

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15
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1

... and if you are searching from the end of a string (LastIndexOf), you would substitute 'index-1' in the third line. – Jess Feb 11 '11 at 20:38
I prefer this approach, because of its efficiency. – Panzercrisis Jan 11 '15 at 00:11

Guffa · Answer 3 · 2010-04-08T12:33:16.353

Get the position of the first space:

int space1 = theString.IndexOf(' ');

The the position of the next space after that:

int space2 = theString.IndexOf(' ', space1 + 1);

Get the part of the string up to the second space:

string firstPart = theString.Substring(0, space2);

The above code put togehter into a one-liner:

string firstPart = theString.Substring(0, theString.IndexOf(' ', theString.IndexOf(' ') + 1));

score 8 · Answer 4 · answered Apr 08 '10 at 12:27

8

s.Substring(0, s.IndexOf(" ", s.IndexOf(" ") + 1))

answered Apr 08 '10 at 12:27

D'Arcy Rittich

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score 3 · Answer 5 · answered Apr 08 '10 at 12:26

3

Use a regex: .

Match m = Regex.Match(text, @"(.+? .+?) ");
if (m.Success) {
    do_something_with(m.Groups[1].Value);
}

answered Apr 08 '10 at 12:26

Marcelo Cantos

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score 3 · Answer 6 · answered Apr 08 '10 at 12:28

3

Something like this:

int i = str.IndexOf(' ');
i = str.IndexOf(' ', i + 1);
return str.Substring(i);

answered Apr 08 '10 at 12:28

den123

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That was a quite simple, efficient and clever solution :) – Siewers Nov 30 '12 at 13:32

Asad · Answer 7 · 2010-04-08T12:33:40.253

2

string testString = "o1 1232.5467 1232.5467.........";

string secondItem = testString.Split(new char[]{' '}, 3)[1];

edited Apr 08 '10 at 12:33

answered Apr 08 '10 at 12:27

Asad

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H H · Answer 8 · 2010-04-08T19:07:30.613

1

 string[] parts = myString.Split(" ");
 string whatIWant = parts[0] + " "+ parts[1];

edited Apr 08 '10 at 19:07

answered Apr 08 '10 at 12:27

H H

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@Jeff: which ones in particular? – H H Apr 08 '10 at 13:18
Use of Pascal case for variables; `MyString` and `WhatIWant`. – Jeff Yates Apr 08 '10 at 13:34
Maybe MyString is a property. Anyway, I don't apply those rules to snippets like this. – H H Apr 08 '10 at 13:37
Apparently not. I guess encouraging best practise is not a priority. Fair enough. – Jeff Yates Apr 08 '10 at 15:16

score 1 · Answer 9 · answered Apr 08 '10 at 17:39

:P

Just a note, I think that most of the algorithms here wont check if you have 2 or more spaces together, so it might get a space as the second word.

I don't know if it the best way, but I had a little fun linqing it :P (the good thing is that it let you choose the number of spaces/words you want to take)

        var text = "a sdasdf ad  a";
        int numSpaces = 2;
        var result = text.TakeWhile(c =>
            {
                if (c==' ')
                    numSpaces--;

                if (numSpaces <= 0)
                    return false;

                return true;
            });
        text = new string(result.ToArray());

I also got @ho's answer and made it into a cycle so you could again use it for as many words as you want :P

        string str = "My Test String hello world";
        int numberOfSpaces = 3;
        int index = str.IndexOf(' ');     

        while (--numberOfSpaces>0)
        {
            index = str.IndexOf(' ', index + 1);
        }

        string result = str.Substring(0, index);

score 0 · Answer 10 · answered Apr 08 '10 at 12:31

There are shorter ways of doing it like others have said, but you can also check each character until you encounter a second space yourself, then return the corresponding substring.

static string Extract(string str)
{
    bool end = false;
    int length = 0 ;
    foreach (char c in str)
    {
        if (c == ' ' && end == false)
        {
            end = true;
        }
        else if (c == ' ' && end == true)
        {
            break;
        }

        length++;
    }

    return str.Substring(0, length);
}

score 0 · Answer 11 · answered Apr 08 '10 at 12:37

You could try to find the indexOf "o1 " first. Then extract it. After this, Split the string using the chars "1232.5467":

        string test = "o1 1232.5467 1232.5467 1232.5467 1232.5467 1232.5467 1232.5467";
        string header = test.Substring(test.IndexOf("o1 "), "o1 ".Length);
        test = test.Substring("o1 ".Length, test.Length - "o1 ".Length);
        string[] content = test.Split(' ');

score 0 · Answer 12 · answered Apr 08 '10 at 13:12

I would recommend a regular expression for this since it handles cases that you might not have considered.

var input = "o1 1232.5467 1232.5467 1232.5467 1232.5467 1232.5467 1232.5467";
var regex = new Regex(@"^(.*? .*?) ");
var match = regex.Match(input);
if (match.Success)
{
    Console.WriteLine(string.Format("'{0}'", match.Groups[1].Value));
}

score 0 · Answer 13 · answered Oct 21 '10 at 13:42

I was thinking about this problem for my own code and even though I probably will end up using something simpler/faster, here's another Linq solution that's similar to one that @Francisco added.

I just like it because it reads the most like what you actually want to do: "Take chars while the resulting substring has fewer than 2 spaces."

string input = "o1 1232.5467 1232.5467 1232.5467 1232.5467 1232.5467 1232.5467";
var substring = input.TakeWhile((c0, index) => 
                                input.Substring(0, index + 1).Count(c => c == ' ') < 2);
string result = new String(substring.ToArray());

score 0 · Answer 14 · answered Mar 03 '22 at 11:33

I did some benchmarks for some solutions in this post and got these results (if performance is important):

Fastest Method (answer from @Hans Olsson):

string str = "My Test String";
int index = str.IndexOf(' ');
index = str.IndexOf(' ', index + 1);
string result = str.Substring(0, index);

@Guffa added a one-liner for this solution (and explained bit by bit of what's going on), which I personally prefer.

Methods checked:

public string Method1(string str)
{
    string[] tokens = str.Split(' ');
    return tokens[0] + " " + tokens[1];
}

public string Method2(string str)
{
    int index = str.IndexOf(' ');
    index = str.IndexOf(' ', index + 1);
    return str.Substring(0, index);
}

public string Method3(string str)
{
    Match m = Regex.Match(str, @"(.+? .+?) ");
    if (m.Success)
    {
        return m.Groups[1].Value;
    }

    return string.Empty;
}

public string Method4(string str)
{
    var regex = new Regex(@"^(.*? .*?) ");
    Match m = regex.Match(str);
    if (m.Success)
    {
        return m.Groups[1].Value;
    }

    return string.Empty;
}

public string Method5(string str)
{
    var substring = str.TakeWhile((c0, index) =>
                        str.Substring(0, index + 1).Count(c => c == ' ') < 2);
    return new String(substring.ToArray());
}

Method execution times with 100000 runs

using OP's input:

string value = "o1 1232.5467 1232.5467 1232.5467 1232.5467 1232.5467 1232.5467";

Method1 took 38ms (00:00:00.0387240)
Method2 took 5ms (00:00:00.0051046)
Method3 took 100ms (00:00:00.1002327)
Method4 took 393ms (00:00:00.3938484)
Method5 took 147ms (00:00:00.1476564)

using a slightly longer input (spaces far into the string):

string value = "o11232.54671232.54671232.54671232.54671232.54671232.5467o11232.54671232.54671232.54671232.54671232.54671232.5467o1 1232.5467 1232.5467 1232.5467 1232.5467 1232.5467 1232.5467";

Method1 took 71ms (00:00:00.0718639)
Method2 took 20ms (00:00:00.0204291)
Method3 took 282ms (00:00:00.2822633)
Method4 took 541ms (00:00:00.5416347)
Method5 took 5335ms (00:00:05.3357977)

How do I extract a substring from a string until the second space is encountered?

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