python - return and print does not give same result

Question

what I'm trying to do is take the entered string separated by commas and change it to list then for each list as a key print the associated value.

def main():
    myDict = {'a':1, 'b':2, 'c':3, 'd':4, 'e':5....}
    u_input = input("Enter a letter")
    myList = [x.strip() for x in u_input.split(',')]
    result = searchDict(myList)
    print(result)

def searchDict(key):
    for ml in key:
        value = myDict.get(ml, "not found")
        re = []
        re.append(value)
        print('-'.join(re)) #this one shows each value for each entered key separated by comma but it does not print it in one line also prints 'None' on the end

    #res = '-'.join(re)
    #return res //this only shows the value for the first key only even if I enter multiple letter

main();

The prob is that, if I return 'res' instead of printing it, I'm only getting the first key value.

output with print(if I enter a, b): 1, 2, none

output with return 1

also , you must be careful about the indentation and syntax and validation of your code !! to refuse down vote ! — Mazdak, Sep 24 '14 at 06:05

score 0 · Accepted Answer · answered Sep 24 '14 at 06:01

0

Are these lines indented properly?

for ml in key:
value = myDict.get(ml, "not found"); 
re = [];
re.append(value)

I think you want it to do this:

re = []
for ml in key:
    value = myDict.get(ml, "not found")    
    re.append(value)
return '-'.join(re)

BTW no semicolons used in Python.

answered Sep 24 '14 at 06:01

Dan

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thanks, worked. I Just typed the code again on here, that's why. – Magna Sep 24 '14 at 06:06

score 0 · Answer 2 · answered Sep 24 '14 at 06:01

0

I think it's because you reset re in every loop. Try to put re=[] outside the for loop.

answered Sep 24 '14 at 06:01

Stephen Lin

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python - return and print does not give same result

2 Answers2

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