Getting String cannot be cast into Integer error

Question

I am getting this error, but don't know why. Here

feedArray.get(mJazzy.getCurrentItem()).get("TotalCount_Smasheys")

returns an Object type. I followed this link to cast Object to Integer.

Screen 1: Here I inspected:

feedArray.get(mJazzy.getCurrentItem()).get("TotalCount_Smasheys")

and got value:

screen 1

Screen 2: Here I inspected: (Integer)(feedArray.get(mJazzy.getCurrentItem()).get("TotalCount_Smasheys")) and it throws exception:

screen 2

EDIT: It is very confusing. feedArray.get(mJazzy.getCurrentItem()).get("TotalCount_Smasheys") returns me an Object, which is actually an Integer, so I can't use (String) on it.

score 1 · Answer 1 · answered Sep 24 '14 at 19:17

1

first use String.trim() Then, instead of casting to Integer Use Integer.parseInt() or Integer.valueOf()
It'll might help.

answered Sep 24 '14 at 19:17

Kasim Rangwala

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so, use **Integer.parseInt(String.valueOf())** this will work on Object type – Kasim Rangwala Sep 24 '14 at 19:20

score 0 · Answer 2 · answered Sep 24 '14 at 19:12

0

That's because the string has spaces. Remove the spaces from the string first and then use Integer.parseInt() to change it to integer.

You can use string.trim() or string.replace(" ","") to remove whitespaces.

answered Sep 24 '14 at 19:12

Pedro Oliveira

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Check screen 1, it is an object with count 2 i.e. "3" and "1" – berserk Sep 24 '14 at 19:13
that's not "3" and "1". That's "31 ". That's a lot different. – Pedro Oliveira Sep 24 '14 at 19:14
No, it's because you can't cast a string to an integer. – Dave Newton Sep 24 '14 at 19:16
That's why I've put Integer.parseInt() in my solution. – Pedro Oliveira Sep 24 '14 at 19:17
As I mentioned, feedArray.get(mJazzy.getCurrentItem()).get("TotalCount_Smasheys") gives me Object not String. – berserk Sep 24 '14 at 19:23
What is feedArray? Is an array of what? – Pedro Oliveira Sep 24 '14 at 19:46
Array of ParseObjects. – berserk Sep 24 '14 at 19:47
Integer.parseInt(String.valueOf(mJazzy.getCurrentItem()).get("TotalCount_Smasheys"))) This works for you? – Pedro Oliveira Sep 24 '14 at 19:59

score 0 · Answer 3 · answered Sep 24 '14 at 19:24

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It lloks like "31" is not an integer but a string. Did you try

int i = Integer.valueOf((String) your_object);

answered Sep 24 '14 at 19:24

yrazlik

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Guilherme · Answer 4 · 2014-09-26T17:51:18.280

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The method

feedArray.get(mJazzy.getCurrentItem()).get("TotalCount_Smasheys")

is returning a String, not an Integer.

Convert it to integer using Integer.parseInt():

String countString = (String) feedArray.get(mJazzy.getCurrentItem()).get("TotalCount_Smasheys");
Integer countInt = Integer.parseInt(countString);

edited Sep 26 '14 at 17:51

answered Sep 24 '14 at 19:28

Guilherme

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It clearly is not an `Integer` otherwise it wouldn't crash that way. Did you try my answer? What error did you get using it? – Guilherme Sep 26 '14 at 12:35
Actually feedArray is an ArrayList of type ParseObject. And ParseObject.get("key") returns an "Object", not an Integer. But the value is actually an Integer, so the Object it returns automatically becomes Integer. Hope u understand what I said lol. – berserk Sep 26 '14 at 13:50
Did you try my answer? – Guilherme Sep 26 '14 at 14:24
Ok, you need to do what Eclipse is suggesting (and I also forgot to do, sorry for that): cast the string. I've updated my answer. – Guilherme Sep 26 '14 at 17:51
The problem is that the Object can be anything, String or Integer. If it returns Integer, then it will cause error here. – berserk Sep 28 '14 at 08:58

Getting String cannot be cast into Integer error

4 Answers4