I'm using a third party DLL which has as parameter a RGB buffer.
I have used the following code to read RGB buffer from Bitmap
:
private byte[] GetBGRValues(Bitmap bmp)
{
// Lock the bitmap's bits.
Rectangle rect = new Rectangle(0, 0, bmp.Width, bmp.Height);
System.Drawing.Imaging.BitmapData bmpData = bmp.LockBits(rect, System.Drawing.Imaging.ImageLockMode.ReadOnly, PixelFormat.Format24bppRgb);
// Get the address of the first line.
IntPtr ptr = bmpData.Scan0;
// Declare an array to hold the bytes of the bitmap.
int bytes = Math.Abs(bmpData.Stride) * bmp.Height;
byte[] rgbValues = new byte[bytes];
// Copy the RGB values into the array.
System.Runtime.InteropServices.Marshal.Copy(ptr, rgbValues, 0, bytes);
bmp.UnlockBits(bmpData);
return rgbValues;
}
The problem is that the generated RGB buffer is not correct. If I open this buffer in IrfanView, supplying correct parameters, the generated image is not correct (looks like it is shifted).
If a get a buffer that I read using C++ code it works.
I have noticed that bmpData.Stride
is 1 unity greater than what I was expecting (width
* channels
). (I know that .NET uses 4 bytes alignment).
The question is: why is the RGB buffer not correct?