convert a time to unix time in CPP

Question

This is very old question and there are similar topics to this here and here and so on. I have:

year like 2014,
month like 10,
...
seconds like 23.

Using these integers I want to get the unix time (the seconds since 1970. 01. 01.). But finally I want only an integer again. How can I do that?

I can use only STL and QT (not Boost). I know there is QDateTime which can solve this, but I still don't know how.

EDIT1: I tried this one, but it seems something went wrong:

const WCCIL::QDate dd(/*fill it*/);
const WCCIL::QTime tt(/*fill it*/);
WCCIL::QDateTime ddtt( dd, tt); // error, no constructor
ddtt.toUTC();

And why the posted answers in the link does not satisfy you ? — quantdev, Oct 03 '14 at 14:34

score 1 · Answer 1 · edited May 23 '17 at 10:27

1

The first link you posted (C++ How can I convert a date in year-month-day format to a unix epoch format?) contains the answer you want. You need to use a tm struct with mktime(). See the mktime() man page for more information.

edited May 23 '17 at 10:27

Community

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answered Oct 03 '14 at 15:06

Rob K

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convert a time to unix time in CPP

month like 10,

1 Answers1