PHP check if one array doesn't have other values than another array

Question

I'm trying to check if an array doesn't have other values than the other but in_array() didn't worked so I guess it can't be done with in_array();

for example

<?php
$arr1 = array(1,2,3,4,5,6);
$arr2 = array(1,2,9);
if(/*all values in $arr2 are in $arr1*/){ 
  /*return true*/
}
else{
  /*return false*/
}
/*this examle should return false*/
?>

or

<?php
$arr1 = array(1,2,3,4,5,6);
$arr2 = array(1,2,6);
if(/*all values in $arr2 are in $arr1*/){ 
  /*return true*/
}
else{
  /*return false*/
}
/*this examle should return true*/
?>

how can I do this?

There's a whack of array functions for this: array_merge, array_diff, array_intersect, etc... — Marc B, Oct 03 '14 at 18:05

score 1 · Accepted Answer · edited May 23 '17 at 10:33

1

Use this

count($array) == count(array_intersect($array,$valid));
.. or come to think of it;
$array == array_intersect($array,$valid);
Note that this would yield true if (string)$elementtocheck=(string)$validelement, so in essence, only usable for scalars. If you have more complex values in your array (arrays, objects), this won't work. To make that work, we alter it a bit:
sort($array);//order matters for strict
sort($valid);
$array === array_intersect($valid,$array);
... assuming that the current order does not matter / sort() is allowed to be called.

edited May 23 '17 at 10:33

Community

1
1

answered Oct 03 '14 at 18:05

XoMEX

321
2
7

I don't have more complex data just numbers thats why I posted an example like this. And thanks it worked. – Laci K Oct 03 '14 at 18:15

score 1 · Answer 2 · answered Oct 03 '14 at 18:12

1

This is the conditional you are looking for:

if (count(array_diff($arr2, $arr1)) == 0) {

answered Oct 03 '14 at 18:12

Dallas Caley

5,367
6
40
69

Thanks, I like your answer but I already accepted one when I saw yours. – Laci K Oct 03 '14 at 18:17

score 0 · Answer 3 · answered Oct 03 '14 at 18:09

0

You can use array_intersect() function:

if (array_intersect($arr1, $arr2) == $arr2) {
  // $arr2 has only elements from $arr1
} else {
  // $arr2 has not only elements from $arr1
}

answered Oct 03 '14 at 18:09

Aleksey Linetskiy

443
3
10

score 0 · Answer 4 · answered Oct 03 '14 at 18:11

Try array_diff:

Example

public function checkSameContents($arr1, $arr2) {
    $diff = array_diff($arr1, $arr2); // returns "unsame" elements in array 
    return count($diff) === 0;
}

This function will return true if the arrays have the same contents, but false if not.

Hope this helps!

score -1 · Answer 5 · answered Oct 03 '14 at 18:07

Have you tried

$arr1 == $arr2

Or you can use a function

<?php
function compareArrays(Array $a, Array $b){
  if(count($a) != count($b)){
    return false;
  }
  foreach($a as $value){
    if( !in_array($value, $b) ){
      return false;
    }
  }
  return true;
}
?>

This is only an example but you could do it this way.

PHP check if one array doesn't have other values than another array

5 Answers5