Regular expression "all three in any order and nothing more"

Question

I need to make a reg expression that will match following conditions:

1) mathing only if it has three words 2) not separated or separated by semicolon (;) 3) in any order 4) all of words should be included, otherwise it will not match

I tried this one:

^(?=(.*;|)one)(?=(.*;|)two)(?=(.*;|)three).*$

but somehow it mathes variants like oneasfafasfsaf;two;three it`s wrong

please, help!

P.S. sometimes it`s needed to have more than three, but i want to understand the core

This is a duplicate of http://stackoverflow.com/questions/13911053/regular-expression-to-match-all-words-in-a-query-in-any-order — jmar777, Oct 07 '14 at 14:36
not, it`s actually not a duplicate, i need to have only these words and nothing more in the string. Sorry, if i forgot to mention. Well "one;two;three", "three;two;one" "threetwoone" should be matched "one;two;four;three","one;one;two;three" - should not be matched — user3414347, Oct 07 '14 at 14:40

score 6 · Accepted Answer · edited May 23 '17 at 11:46

6

You could capture all 3 and check for each exists, then, if string is only composed of the 3 words:

^(?=.*?(one))(?=.*?(two))(?=.*?(three))(?:(?:\1|\2|\3);?){3}$

See test at regex101.com (explanation on the right); Regex FAQ

edited May 23 '17 at 11:46

Community

1
1

answered Oct 07 '14 at 14:47

Jonny 5

12,171
2
25
42

score 1 · Answer 2 · answered Oct 07 '14 at 15:03

1

(one|two|three);?(?!\1)(one|two|three);?(?!\2)(one|two|three)

Try this.See demo.

http://regex101.com/r/hQ1rP0/41

answered Oct 07 '14 at 15:03

vks

67,027
10
91
124

Regular expression "all three in any order and nothing more"

2 Answers2