I am working one a page like the below
<div id="first_div">
<form name='invoice_edit' id='invoice_edit' action='forms_invoice.php' method='post'>
<table border="0">
<tr>
<td id=customers_title_td >Customer</td>
<td id=customers_td > <!-- php code for customer list //-->
</td>
</tr>
</table>
<input type="submit" value="get" />
</form>
</div>
<div id="second_div">
<form name='customers_edit' id='customers_edit' action='forms_customer.php' method='post'>
<table>
<tr>
<td >Name</td>
<td ><input name="customers_name" type="text" value="" id="customers_name"></td>
</tr>
<tr>
<td >Bill To</td>
<td ><input name="customers_billto_addr" type="text" value="" id="customers_billto_addr"></td>
</table>
<input type="button" onClick="goCustomerUpdate('I');" value=" Create " name="Insert" />
</form>
</div>
Left Div(first_div) contains Invoice Data and Right side Div(second_div) is for displaying additional info or update like displaying a customer info or if it's a new customer, create a new customer data.
What I want to do is when submitting a new customer info, i want to the left side div stay unchanged while submitting right side customer form and after done creating customer log, update customer list(drop down) in the left side div(invoice)
The part I don't know is " do I submit to a page(forms_customer.php) or is there a way to wrap all elements in second_div and send them with jquery maybe with post method?