Parse URL From Right - Jquery/Regex

Question

I have a URL that is very similar to:

url/Search/SearchResult?SearchText=FirstName%20Lastname

Using JQ, how can I parse Everything after the "SearchText=" , while replacing %20 with a space.

I'm looking to return a string in the following format:

"FirstName LastName"

I figure this can be done easily with RegEx, but I struggle working with it, so examples would be very helpful.

Thanks

`decodeURIComponent(string)` – Pedro Estrada Oct 08 '14 at 14:45 — Pedro Estrada, Oct 08 '14 at 14:45

score 1 · Accepted Answer · answered Oct 08 '14 at 14:46

1

You can do this

var value = decodeURIComponent(url.split('?')[1].split('=')[1]);

answered Oct 08 '14 at 14:46

Amit Joki

score 0 · Answer 2 · answered Oct 08 '14 at 14:44

0

.*=|%20

Try this.Replace by .See demo.

answered Oct 08 '14 at 14:44

vks

This will add a space at the begining. – Casimir et Hippolyte Oct 08 '14 at 14:45
@CasimiretHippolyte that is a smaller problem and can be tackled easily – vks Oct 08 '14 at 14:45

score 0 · Answer 3 · answered Oct 08 '14 at 14:48

0

Try this :

var searchText = document.URL.split("SearchText=")[1].split("%20");
var name = searchText[0] + " " + searchText[1];

answered Oct 08 '14 at 14:48

skirato

That's only work if the SearchText was definitely the last parameter, and if there were no escaped characters in the string: you'd need to `uriDecodeComponent` the strings afterwards. But there are more complete solutions on a few other questions here. – Rup Oct 08 '14 at 16:31
Can you expand your answer to include an explanation of your code? It helps the reader more than you might think. – gunr2171 Oct 08 '14 at 17:02

3 Answers3