How to get current URL in jinja2/flask (request.url not working)

Question

Is there a way to print the current URL in Jinja2/Flask?

E.g. if the current URL is http://www.domain.com/example/1/2

{{ request.path }} works and prints /example/1/2, but how to I get the full URL with http:// as well?

From the docs (here){{ request.url }} should work, but it doesn't yield anything.

Thanks

UPDATE

Here are the render/context args from views.py:

class EventDetailView(EventObjectMixin, FormView):
    template_name = 'gig/public/about.html'
    context_object_name = 'event'
    form_class = EventPurchaseTicketForm

    def get_context_data(self, **kwargs):
        context = super(EventDetailView, self).get_context_data(**kwargs)

    ...

        return context

Does `{{request.path}}` actually work **in your template?** You might simply be missing `request` in your context. Please show us the code that calls the Jinja template's render method (or at least the code that generates the context for it). — Thomas Orozco, Oct 09 '14 at 11:01
Yes, it works. I am editing someone else's code - where is the render method usually found? In models.py? — alias51, Oct 09 '14 at 11:06
More likely in the view code (the request handler with the logic for that URL) — Thomas Orozco, Oct 09 '14 at 11:06
Ok, thanks, what would the typical function/argument be that I'm looking for? — alias51, Oct 09 '14 at 11:10
Anything that says `render`, `render_template`, or `context` is likely. — Thomas Orozco, Oct 09 '14 at 11:15
Unfortunately this isn't really helpful. We'd need to see the code for the original `get_context_data` method, as well as where that context is used. — Thomas Orozco, Oct 09 '14 at 12:40

score 38 · Accepted Answer · answered Jan 15 '18 at 10:16

38

You can use {{ url_for(request.endpoint) }}, it works.

answered Jan 15 '18 at 10:16

hugoxia

428
4
2

9

Note that you get an error if the route associated with `request.endpoint` requires a few parameters. This [answer to a similar question](https://stackoverflow.com/a/25013141/4453460) provides a better idea. – lfurini Mar 11 '19 at 14:32

score 26 · Answer 2 · answered Jul 01 '21 at 19:21

26

For folks who have routes that require additional arguments, the accepted answer won't quite work, as mentioned by @lfurini.

The following will use the view's arguments when constructing the URL:

{{ url_for(request.endpoint, **request.view_args) }}

answered Jul 01 '21 at 19:21

Kirkman14

1,506
4
16
30

1

Better than accepted answer for me. The **request.view_args was helpful – Copas May 14 '22 at 12:31

score 3 · Answer 3 · answered Oct 09 '14 at 11:18

Find where you have similar code to this, usually found in controller.py or __ init__.py or views.py :

from flask import render_template
...

@app.route('/example/<arg1>/<arg2>')
def some_view_function(arg1, arg2):
    ...

    return render_template('path/to/your/template.html')

With render_template() are request and other variables available to you.

How to get current URL in jinja2/flask (request.url not working)

3 Answers3