Concatenate PHP inside of echo

Question

I've attempted to add an if/else statement within an already opened echo function, but page comes up blank. Not too sure if I am concatenating properly.

echo '<span class="year-tab-'.$x.' '.if ($single_year==$year_selected) { echo "" } else { echo "display-none" }.' ">';

score 5 · Answer 1 · answered Oct 14 '14 at 00:46

5

You cannot have control structures inside concatenation

$style = ($single_year==$year_selected) ? '' : "display-none";
echo '<span class="year-tab-'.$x.' '.$style.'">';

That concatenation is a bit messy. printf() might be a bit cleaner

printf('<span class="year-tab-%s %s">', 
    %x,
    ($single_year==$year_selected) ? '' : "display-none"
);

answered Oct 14 '14 at 00:46

John Conde

217,595
99
455
496

Actually, you can use ternary operator inside echo's, there's no need to use another variable in your first example (for readability would be better to use an if though) – hlscalon Oct 14 '14 at 00:51

score 3 · Accepted Answer · answered Oct 14 '14 at 00:51

3

Or you can do this:

echo '<span class="year-tab-'.$x.' '.($single_year==$year_selected ? "" : "display-none").' ">';

See Ternary Operator on this page.

answered Oct 14 '14 at 00:51

Dwayne Towell

8,154
4
36
49

score 0 · Answer 3 · answered Oct 14 '14 at 01:31

0

Using the ternary operator:

echo '<span class="year-tab-'.$x;
echo ($single_year==$year_selected)? '>' : ' style="display:none">';

Note that for display value, you have to enclose it inside the display tag.

answered Oct 14 '14 at 01:31

DonMiguel

11
1

Concatenate PHP inside of echo

3 Answers3