Execute multiple command onto same terminal using bash script

Question

I am trying to run a bash script which contains few commands to execute. I want to open a terminal and execute multiple commands into it. I have written commands to set the directory path and want to make a folder there.

Code :

gnome-terminal --working-directory=/var/run/ 
gnome-terminal -e "bash -c \"sudo mkdir sphinxsearch; exec bash\""

Here, There are 2 problems :

1) Two separate terminal are opened that I don't want. I need only a single terimal where I will execute my commands.

2) sudo mkdir sphinxsearch folder is created at the default path from where I am executing my bash script. I need to create a folder inside /var/run/

Why don't you put the `--working-directory` option on the second command? — Barmar, Oct 15 '14 at 06:10
Because I want to make folder inside **/var/run**. I got the answer. — iNikkz, Oct 15 '14 at 06:28

score 1 · Accepted Answer · answered Oct 15 '14 at 06:12

1

Each invocation of gnome-terminal will open a separate terminals.

Try this:

gnome-terminal --working-directory=/var/run/ -e "bash -c \"sudo mkdir sphinxsearch; exec bash\""

Here i am combining both options in a single invocation of gnome-terminal

answered Oct 15 '14 at 06:12

Fazlin

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score 1 · Answer 2 · answered Oct 15 '14 at 06:12

1

sudo mkdir /var/run/sphinxsearch;

will create the folder in /var/run/

answered Oct 15 '14 at 06:12

nu11p01n73R

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Execute multiple command onto same terminal using bash script

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