Go xml.Marshal returns invalid characters

Question

I use the code below generate a XML encoding of string str:

str := string([]byte{0x01})
marshalBytes, _ := xml.Marshal(str)
fmt.Println(string(marshalBytes)) // output: <string>�</string>; � is [239 191 189] in bytes.

Obviously, � is not equivalent of 0x01.

How can I fix it?

Are you on Windows, in a DOS windows? (as in http://stackoverflow.com/q/12053168/6309) — VonC, Oct 16 '14 at 12:53

Charlie Tumahai · Accepted Answer · 2014-10-16T13:01:44.580

5

The bytes [239 191 189] are the UTF-8 encoding of the Unicode Replacement Character.

The XML marshaler replaces the byte 0x1 with the Unicode Replacement Character because the byte 0x01 is not a legal character in XML.

It is not possible to prevent the XML marshaler from using the replacement.

edited Oct 16 '14 at 13:01

answered Oct 16 '14 at 12:55

Charlie Tumahai

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If I want to transfer byte 0x01 in a xml file, How can I achieve that? – liudanking Oct 17 '14 at 02:37

Go xml.Marshal returns invalid characters

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