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I'm hoping to find a way to use a while loop (not a for loop) to get the individual digits of an integer put in through command line. Right now, I have it hard coded for how to get individual digits if a four digit integer is entered, but if I enter a five digit number it obviously won't work. I'm thinking a while loop should be able to fix that but I'm not sure how...

Here is the code I have so far

Bianca Fuller
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    You'll need an array or some kind of `List`. You won't be able to do this with individual variables named `digit1`, `digit2`, etc. – ajb Oct 17 '14 at 23:01
  • http://stackoverflow.com/a/3389287/1114171 – T I Oct 17 '14 at 23:02

2 Answers2

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Try this:

List<Integer> digits = new ArrayList<Integer>();
while (number > 0)
{
    digits.add(number%10);
    number /= 10;
}
barak manos
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Try this out:

int number = 567;
int[] digits = new int[String.valueOf(number).length()];
while (number > 0)
{
    digits[String.valueOf(number).length()-1] = number % 10;
    number /= 10;
}
System.out.println(Arrays.toString(digits));

Might not be the most elegant solution, but it will give you the digits in the number, in the same order as they are in the number. Example 12345 will give the array a value of [1, 2, 3, 4, 5] when it is output.

Shadow
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