Encode/Decode enum for Swift (Xcode 6.1)

Question

I have

var priority : Priority! = Priority.defaultPriority

func encodeWithCoder(aCoder: NSCoder) {
        aCoder.encodeInteger(priority.toRaw(), forKey: "priority") //toRaw may not yield the result I am expecting
    }

    required init(coder aDecoder: NSCoder) {
        priority = aDecoder.decodeIntegerForKey("priority") //complaining about conflicting types
    }

with the enum being the following:

enum Priority : Int {
        case defaultPriority = 0
        case lowPriority = 1
        case mediumPriority = 2
        case highPriority = 3
    }

What is the best way to encode/decode this?

Similar question: http://stackoverflow.com/questions/26326645/how-do-i-encode-enum-using-nscoder-in-swift. — Martin R, Oct 18 '14 at 08:59

score 17 · Accepted Answer · edited Nov 23 '15 at 14:07

17

Priority.init(rawValue:) should work.

func encodeWithCoder(aCoder: NSCoder) {
    aCoder.encodeInteger(priority.rawValue, forKey: "priority")
}

required init(coder aDecoder: NSCoder) {
    priority = Priority(rawValue: aDecoder.decodeIntegerForKey("priority"))
}

edited Nov 23 '15 at 14:07

stephencelis

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answered Oct 18 '14 at 08:50

rintaro

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1

Thanks for adding the update for 6.1. – jpittman Oct 21 '14 at 07:00

Encode/Decode enum for Swift (Xcode 6.1)

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