Regex how to get parameter from url string. Jascript

Question

Hello I have a URL string:

'http://www.hello.com/index.php?page=11'

What is the regular expression that I have to execute to get the page number?

you can do it without any regexp `'http://www.hello.com/index.php?page=11'.split('page=')[1]` — Mritunjay, Oct 19 '14 at 08:50

score 0 · Answer 1 · answered Oct 19 '14 at 08:49

0

(\d+)[^\d]*$

Try this.Grab the capture.See demo.

http://regex101.com/r/wQ1oW3/10

answered Oct 19 '14 at 08:49

vks

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what if there are other arguments after page ? – php_nub_qq Oct 19 '14 at 08:51
1

No, it doesn't. It picks everything up. – php_nub_qq Oct 19 '14 at 08:53
1

This doesn't work, as well, if arguments after page contain digits. – php_nub_qq Oct 19 '14 at 08:55

Avinash Raj · Answer 2 · 2014-10-19T09:00:41.243

0

Use capturing group to capture one or more digits which are present just after to ?page=.

> var s = 'http://www.hello.com/index.php?page=11'
undefined
> var re = /\?page=(\d+)/;
undefined
> console.log(re.exec(s)[1])
11
> var re = /\bpage=(\d+)/;
undefined
> console.log(re.exec(s)[1])
11

edited Oct 19 '14 at 09:00

answered Oct 19 '14 at 08:51

Avinash Raj

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Regex how to get parameter from url string. Jascript

2 Answers2