Why doesn't it throw OverFlow Exception?

Asked Oct 21 '14 at 11:10

Active Oct 21 '14 at 11:15

Viewed 155 times

Sample 1

int a = Int32.MinValue;
int b = -a;
Console.WriteLine("a={0}",a);
Console.WriteLine("b={0}", b);

Result

a=-2147483648
b=-2147483648

Sample 2

int a = Int32.MinValue;
int b = a-1;
Console.WriteLine("a={0}",a);
Console.WriteLine("b={0}", b);

Result

a=-2147483648
b=2147483647

In two samples: why doesn't it throw overflow exception. When I tried these samples in java environment, I got same results. Is there anyone who can explain this situation?

edited Oct 21 '14 at 11:11

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asked Oct 21 '14 at 11:10

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This is not `Java`. Please use valid tags only. – Ruchira Gayan Ranaweera Oct 21 '14 at 11:11
Try wrapping the .Net code in a `checked{}` block? – StuartLC Oct 21 '14 at 11:11
He said he *"tried these samples in java environment"*. Anyway he should add the Java code if he did, not just the C# code. – ADTC Oct 21 '14 at 11:12
You'll get an overflow error if you put it into `checked` block: `checked {int b = -a ...}` – Dmitry Bychenko Oct 21 '14 at 11:14
http://msdn.microsoft.com/en-us/library/h25wtyxf.aspx – Dmitry Bychenko Oct 21 '14 at 11:15

Why doesn't it throw OverFlow Exception?

0 Answers0