java comparing values in arrays

Question

Wasn't sure whether to make a new thread or not. but i'll post it here. I figured my explanation was not very good.

i have a class below

lets say int[] = 1204, 1205

public class Job {

 private  int[] serviceCode =;     

 public Job (int[] jobCode) {


serviceCode = jobCode;

}

  public  int[] getJobCode() {
    return serviceCode;
 }

and this is the main program

public class MainProgram { 

public static void main {



}

}

how do i put the values of the array into separate integers?

you can't just simply say h==t, because h is array and t is an integer... — nafas, Oct 21 '14 at 15:38
Please explain clearly what you mean by "I'm trying to compare values from `int[] h` to `int t`". Which values? All of them? Are you trying to see if every value in the array equals `t`, or if any value in the array equals `t`, or the first value in the array equals `t`, or what????? — ajb, Oct 21 '14 at 15:41
sorry for the bad explanation. i have edited my question that will help with my problem. thanks — Nghia, Oct 22 '14 at 12:31

score 3 · Answer 1 · answered Oct 21 '14 at 15:39

3

You can't directly compare an int[] to an int. You need to access a value in the array and then compare.

int[] myArray = {1, 2, 3};
int value = 1;
if (myArray[0] == value) {/*do something*/}

answered Oct 21 '14 at 15:39

Grice

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24

score 2 · Answer 2 · answered Oct 21 '14 at 15:40

You cannot compare an array with a variable that holds just one data.

You know, array is a data structure.

You must loop through the array and then compare each value of the array with t.

for(int i = 0; i < h.length; i++) {

    if( t == h[i] ) // Or any other comparison operator
        /* Perform some action.*/;
}

score 1 · Answer 3 · edited May 23 '17 at 12:20

Your int[] h is an array of integers while int t is just a integer variable. So comparison is not at all possible. As per your question's title java comparing values in arrays here is an answer.

Either you can check whether this value exist in an array in for loop.

int val = 1;
int[] valArray = {1,2,3,4,5};
for(int i = 0; i < valArray.length ; i++)
{
     if (valArray[i] == val)
       {// Matched
       }
     else
      { // Not matched
      }

}

Amit Sharma · Answer 4 · 2014-10-23T09:31:18.240

Array is contiguous memory location, in order to get the specific values from the each addressable unit you have to access that addressable location. Suppose you declare an array like this.

int[] array = {10,20,30};

This will do the memory allocation like this: ( lets 0th element is at address 100 and assuming int size is of 4 byte)

index        0      1      2
         -----------------------
         |  10  |  20   |  30   |
         -----------------------
address:    100    104    108

Array array name is basically base address form where the array starts in this case it is 100, next element will be present at 104 and 108.

Now lets say we have an integer variable : int temp=100. Now to compare array element with integer variable temp, we have to access the each element of array of type integer situated at specific index. You have to compare like following:

for(int i=0; i<array.length; i++){
    if(temp>array[i])  /*array[i] is accessing the value at index i"*/ 
           //do something
    else
          //do something.
}

java comparing values in arrays

4 Answers4