counting the number of lines between two characters

Question

I would like to count the number of the lines found between each two consecutive "*" characters including one of them. Input:

>*1
AA
BB
CC
>*2
RR
FGRE
>*3
A

output:

4 >*1
3 >*2
2 >*3

where the first field is the number of the lines between *'s and the second field is the string including them.

Why do you have all those tags? – admdrew Oct 22 '14 at 18:49 — admdrew, Oct 22 '14 at 18:49
Sorry! I was not sure what to use. Is it better now? – ahb65 Oct 22 '14 at 18:56 — ahb65, Oct 22 '14 at 18:56

score 2 · Accepted Answer · answered Oct 22 '14 at 18:51

2

Using awk you can do:

awk '/\*/{if (p) print c, p; p=$0;c=0} {c++} END{if (p) print c, p}' file
4 >*1
3 >*2
2 >*3

answered Oct 22 '14 at 18:51

anubhava

761,203
64
569
643

score 1 · Answer 2 · answered Oct 22 '14 at 19:02

try this:

cat  x1.txt | perl -ne '
  chomp;
  if ( $_ =~ /^>\*/ ) {
    $l1{$_}++;
  };
  $prev=$_;
  while(<>){
    chomp;
    if ( $_ =~ /^>\*/ ) {
       $prev=$_;
       $l1{$prev}++;
    } else { 
       $l1{$prev}++;}
    };             
    if (eof) {
      foreach $m1  ( keys %l1 ){
        print qq($m1 , $l1{"$m1"}\n);
      };
 };'

score 1 · Answer 3 · answered Oct 22 '14 at 22:52

1

Here's my command:

nl | sed -n '/*/p;/*/{1!p};$p' | xargs -n4 | awk '{print $3-$1, $2}'

answered Oct 22 '14 at 22:52

Vytenis Bivainis

2,308
21
28

Or `nl | sed -n '/*/{p;1!p};$p' | xargs -n4 | awk '{print $3-$1, $2}'` – Vytenis Bivainis Oct 22 '14 at 22:53

counting the number of lines between two characters

3 Answers3

Linked