Issue with printf precision control

Question

I need to print out a multiplication table that looks like this in C:

   1  2  3  4  5  6  7  8  9 10
1  1  2  3  4  5  6  7  8  9 10
2     4  6  8 10 12 14 16 18 20
3        9 12 15 18 21 24 27 30
4          16 20 24 28 32 36 40
5             25 30 35 40 45 50
6                36 42 48 54 60
7                   49 56 63 70
8                      64 72 80
9                         81 90
10                          100

My loop to print the numbers in the correct format is a bit tedious right now:

printf("   1   2   3   4   5   6   7   8   9  10\n");
for(i=1; i<=10; i++)
{
    printf("%4d", i);
    for (j=i; j<=10; j++)
    {           
        result = i*j;
        if (i == 2 && j == 2)
        {
            printf("%8d", result);    
        }
        else if (i == 3 && j == 3)
        {
            printf("%12d", result);                
        }
        else if (i == 4 && j == 4)
        {
            printf("%16d", result);    
        }
        else if (i == 5 && j == 5)
        {
            printf("%20d", result);    
        }
        else if (i == 6 && j == 6)
        {
            printf("%24d", result);                
        }
        else if (i == 7 && j == 7)
        {
            printf("%28d", result);    
        }
        else if (i == 8 && j == 8)
        {
            printf("%32d", result);
        }
        else if (i == 9 && j == 9)
        {
            printf("%36d", result);
        }    
        else if (i == 10 && j == 10)
        {
            printf("%40d", result);
        }
        else
        {
            printf("%4d", result); 
        }
    }
    printf("\n");
}

I was thinking there has to be a way to make this easier, to somehow concat an int variable into the precision of the number, like this:

if (i == j)
{
    printf("%(4 * i)d", result);
}
else
{
    printf("%4d", result);
}

This code obviously won't work, but is there a way I can achieve something like this so I can avoid all the if/else statements in my current loop?

Do like `printf("%*s%d", (4 * i), " ", result);` Check [this code](http://codepad.org/G8nNud3V) I have written for you. The point you need to learn is "%*s" — Grijesh Chauhan, Oct 26 '14 at 06:02
I'm strongly tempted to close as a duplicate of [Is there a way to specify how many characters of a string to print out using `printf()`?](http://stackoverflow.com/questions/2239519/is-there-a-way-to-specify-how-many-characters-of-a-string-to-print-out-using-pri/2239571#2239571). It is good that you recognize that your code is clumsy and that you want to know how to improve it. — Jonathan Leffler, Oct 26 '14 at 11:54

score 3 · Answer 1 · answered Oct 26 '14 at 06:04

This may not be exactly what you want but it should help you:

#include <stdio.h>

int main() {
    int i, j, result;
    printf("          1   2   3   4   5   6   7   8   9  10\n");
    for(i=1; i<=10; i++) {
        printf("%3d %*s", i, i * 4, " ");
        for (j=i; j<=10; j++) {
            printf("%3d ", i * j); 
        }
        printf("\n");
    }   
    return 0;
}

Output:

          1   2   3   4   5   6   7   8   9  10
  1       1   2   3   4   5   6   7   8   9  10 
  2           4   6   8  10  12  14  16  18  20 
  3               9  12  15  18  21  24  27  30 
  4                  16  20  24  28  32  36  40 
  5                      25  30  35  40  45  50 
  6                          36  42  48  54  60 
  7                              49  56  63  70 
  8                                  64  72  80 
  9                                      81  90 
 10                                         100

score 0 · Answer 2 · answered Oct 26 '14 at 14:02

Here is code that implements almost what you have as the desired output:

#include <stdio.h>

int main(void)
{
    printf("%4s", " ");
    for (int i = 1; i <= 10; i++)
        printf("%4d", i);
    putchar('\n');

    for (int i = 1; i <= 10; i++)
    {
        printf("%-*d", 4 * i, i);
        for (int j = i; j <= 10; j++)
            printf("%4d", i * j);
        putchar('\n');
    }

    return 0;
}

Output:

       1   2   3   4   5   6   7   8   9  10
1      1   2   3   4   5   6   7   8   9  10
2          4   6   8  10  12  14  16  18  20
3              9  12  15  18  21  24  27  30
4                 16  20  24  28  32  36  40
5                     25  30  35  40  45  50
6                         36  42  48  54  60
7                             49  56  63  70
8                                 64  72  80
9                                     81  90
10                                       100

The difference is in the space at the start of the lines. Your desired output has 2 spaces for the row number, followed by 2 spaces for the 1 in the row labelled 1, followed by 4 spaces for each other entry. Mimicking that exactly is a little fiddly — doable, but fiddly:

#include <stdio.h>

int main(void)
{
    for (int i = 1; i <= 10; i++)
        printf("%4d", i);
    putchar('\n');

    for (int i = 1; i <= 10; i++)
    {
        printf("%-*d", 4 * i - ((i == 1) ? 2 : 4), i);
        for (int j = i; j <= 10; j++)
            printf("%*d", (j == 1) ? 2 : 4, i * j);
        putchar('\n');
    }

    return 0;
}

The conditional expressions are not very elegant.

Issue with printf precision control

2 Answers2