If image isn't avaiable display image placeholder

Question

Hey guys I am pulling images to my front end using this PHP:

echo '<img class="ms-thumb" src="'.(explode(',', $cardata["PictureRefs"])[0]).'" alt="'.$cardata["Variant"].'" />';

So I'm taking images from my database and displaying them in a list, in rare cases some SQL rows wont have an image url.

Can anyone show me an example of code that I could use to display a placeholder image if the src="" is empty?

I'm not great with JS and I'm guessing I'll need to use it to accomplish this.

Any example of how this could be done would be great.

Looking for some stuff like this ? http://stackoverflow.com/questions/3984287/how-to-show-alternate-image-if-source-image-is-not-found-onerror-working-in-ie — PrakashSharma, Oct 26 '14 at 15:29

A.B · Accepted Answer · 2014-10-26T16:41:49.790

2

edit simple line, this will place image if image is empty (not there). replace src attribute with this one

   src="'.(!empty( $cardata["PictureRefs"]))?(explode(',', $cardata["PictureRefs"])[0]):'img/placeholder.jpg' .'"

where your path to img is

'img/placeholder.jpg'

change it to your placeholder path

edited Oct 26 '14 at 16:41

answered Oct 26 '14 at 15:30

A.B

I've just tried using the code and I'm getting a syntax error, any ideas why? – Peter Hardy Oct 26 '14 at 16:18
This is the error: Parse error: syntax error, unexpected ':', expecting ',' or ';' – Peter Hardy Oct 26 '14 at 16:20
have you edited my code or it is itself giving error? – A.B Oct 26 '14 at 16:21

1 Answers1