Extracting the pattern from the line

Question

How can I extract words which contains the pattern "arum" from the following line:

Agarum anoestrum  alabastrum sun antirumor alarum antiserum ambulacrum antistrumatic Anatherum antistrumous androphorum antrum 4. foodstuff foody nonfood Aplectrum

So words like sun, 4., foody, nonfood should be removed.

Duplicate of http://stackoverflow.com/q/1546711/2706918 – Nitinkumar Ambekar Nov 05 '14 at 12:25 — Nitinkumar Ambekar, Nov 05 '14 at 12:25

score 0 · Accepted Answer · answered Nov 05 '14 at 12:21

You can use grep:

echo "Agarum anoestrum sun" | tr ' ' '\n' | grep "arum"

tr is used to split the input string in one word per line, since grep operates on a per-line basis and would display the whole line.
If you want the output to be in one line again, use:

echo "Agarum anoestrum sun" | tr ' ' '\n' | grep "arum" | tr '\n' ' '

score 0 · Answer 2 · answered Nov 05 '14 at 12:24

0

Using grep -Eo:

grep -Eo 'a[[:alnum:]]*rum' file
arum
anoestrum
alabastrum
antirum
alarum
antiserum
ambulacrum
antistrum
atherum
antistrum
androphorum
antrum

answered Nov 05 '14 at 12:24

anubhava

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score 0 · Answer 3 · answered Nov 05 '14 at 12:34

Try:

echo Agarum anoestrum alabastrum sun antirumor alarum antiserum ambulacrum antistrumatic Anatherum antistrumous androphorum antrum 4. foodstuff foody nonfood Aplectrum | awk '{for (i=1;i<NF;i++) { if (match($i, "[aA][[:alnum:]]*[rR][uU][mM]") != 0) { printf ("%s ", $i) }} print}'

Extracting the pattern from the line

3 Answers3