How to initialize an array in C with one line?

Question

This is my code

int numLeft[5];
void init() 
{
     numLeft = {5,4,3,3,2};
}

When I tried compiling this code, I got this error: "error: expected expression before '{' token. I know in java something like this could work

int[] numLeft;
void init() {
       numLeft = {5,4,3,3,2};
}

Is there something i am missing in my C code? A quick google search isn't helping.

[duplicated?](http://stackoverflow.com/questions/3137671/declaring-and-initializing-arrays-in-c) Use `memcpy`. — code monkey, Nov 06 '14 at 07:42

score 2 · Accepted Answer · edited Feb 21 '22 at 21:28

2

int numleft[5] = {5,4,3,3,2}

is the way to go. Here numleft is the variable that is referring to the array, but to access each, you've to refer to it as numleft[0], numleft[1], likewise.

edited Feb 21 '22 at 21:28

Neuron

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answered Nov 06 '14 at 07:42

GeeYes

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I need to declare numLeft as a global variable and initialize it in the function though – committedandroider Nov 06 '14 at 07:43

score 1 · Answer 2 · edited Feb 21 '22 at 21:27

1

int numLeft[5] = {5,4,3,3,2}; wiil do the job

if you need to initialize the global array each time, need to use memcpy(), as suggested in the other duplicate answers.

edited Feb 21 '22 at 21:27

Neuron

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answered Nov 06 '14 at 07:39

Sourav Ghosh

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I need the numLeft as a global variable though and initialize it each time in the function – committedandroider Nov 06 '14 at 07:41

How to initialize an array in C with one line?

2 Answers2