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i'm trying to implement bicubic interpolation;

this is a follow-up question to my question:MATLAB vs C++ vs OpenCV - imresize
about imresize, so i know openCV doesn't do cubic interpolation like matlab. and i need to get to the same results like matlab. for imresize.

so for an example I want to get just the first pixel of my image

int* Utilities::MatlabImresize(int* channel,int width, int height, double scale)
{
    double test[4][4] = {{channel[0],channel[1], channel[2], channel[3]},
                        {channel[width],channel[width+1], channel[width+2], channel[width+3]},
                        {channel[2*width],channel[2*width+1], channel[2*width+2], channel[2*width+3]},
                        {channel[3*width],channel[3*width+1], channel[3*width+2], channel[3*width+3]}};
    double x = bicubicInterpolate(test,0.5,0.5);

    return NULL;
}


double Utilities::cubicInterpolate (double p[4], double x) 
{
    return p[1] + 0.5 * x*(p[2] - p[0] + x*(2.0*p[0] - 5.0*p[1] + 4.0*p[2] - p[3] + x*(3.0*(p[1] - p[2]) + p[3] - p[0])));
}

double Utilities::bicubicInterpolate (double p[4][4], double x, double y) 
{
    double arr[4];
    arr[0] = cubicInterpolate(p[0], y);
    arr[1] = cubicInterpolate(p[1], y);
    arr[2] = cubicInterpolate(p[2], y);
    arr[3] = cubicInterpolate(p[3], y);
    return cubicInterpolate(arr, x);
}

I still don't get the same results so I'm guessing my kernel isn't the same as the one matlab are using. how can i get the same results?

**my original 4x4<**br>

155 306 155 306
293 213 293 213
172 325 172 324
291 198 290 198

the results i'm getting from matlab:

151.196136474609 155.925476074219 155.555526733398 145.714401245117
151.044921875000 155.254089355469 157.459579467773 154.982849121094
149.490341186523 151.587142944336 150.641662597656 155.392364501953
153.666915893555 156.283508300781 156.848739624023 155.557098388672
147.997482299805 154.688049316406 157.798034667969 152.912796020508

my result for pixel 0,0 is 155.3437500000000

update:
using @andrey's advice i went into the imresize code
this is what was written there:

Cubic Convolution Interpolation for Digital Image % Processing," IEEE Transactions on Acoustics, Speech, and Signal % Processing, Vol. ASSP-29, No. 6, December 1981, p. 1155.

http://www.academia.edu/2266812/Cubic_convolution_interpolation_for_digital_image_processing

absx = abs(x);
absx2 = absx.^2;
absx3 = absx.^3;

f = (1.5*absx3 - 2.5*absx2 + 1) .* (absx <= 1) + ...
                (-0.5*absx3 + 2.5*absx2 - 4*absx + 2) .* ...
                ((1 < absx) & (absx <= 2));

I do not understand how this function:

float Utilities::Cubic(const float& x, const float& scale)
{
  /*
  % See Keys, "Cubic Convolution Interpolation for Digital Image
  % Processing," IEEE Transactions on Acoustics, Speech, and Signal
  % Processing, Vol. ASSP-29, No. 6, December 1981, p. 1155.
  */

  float absx = fabs(x*scale);
  float absx2 = pow(absx, 2);
  float absx3 = pow(absx, 3);

  float f = (1.5*absx3 - 2.5*absx2 + 1) * (absx <= 1) +
            (-0.5*absx3 + 2.5*absx2 - 4*absx + 2) *
            ((1 < absx) & (absx <= 2));

  return f*scale;
}

x is the distance between the point to be interpolated and the grid point being considered

can handle 4X4 matrix like the other cubic interpolation I have?

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Gilad
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    You can look how it implemented in MATLAB. Type imresize in script, then click right mouse button on it and in context menu select open "imresize". – Andrey Smorodov Nov 08 '14 at 09:42
  • http://stackoverflow.com/questions/26823140/imresize-trying-to-understand-the-bicubic-interpolation here's the follow-up questions for future reference – Gilad Nov 10 '14 at 22:19

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