Array 2D looping

Question

I have a problem to understand array 2D looping concept. This is my code :

int[][] matA = new int[2][3];
matA[0][0] = 2;
matA[0][2] = 3;
matA[1][1] = -4;

for (int i = 0; i < matA.length; i++){
    for (int j = 0; j < matA[0].length; j++){
        System.out.print("\t" + matA[i][j]);
    }

    System.out.println("");
}

I know that matA[0].length used for displaying what is second array or [3] contain, I just don't understand how [0] on metA[0].length can displaying the second array

It works because `matA[0]` and `matA[1]` are the same length in your example (3). So `j` is 0, 1 and then 2 (when j is 3 the loop stops). — Elliott Frisch, Nov 09 '14 at 02:43
this thread might help you understand 2d array better http://stackoverflow.com/questions/12231453/creating-two-dimensional-array — Pasang Sherpa, Nov 09 '14 at 02:57

score 0 · Answer 1 · edited Nov 09 '14 at 02:47

0

Try to do it

int[][] matA = new int[2][3];
matA[0][0] = 2;
matA[0][2] = 3;
matA[1][1] = -4;

for (int i = 0; i < matA.length; i++){
    for (int j = 0; j < matA[i].length; j++){
        System.out.print("\t" + matA[i][j]);
    }

    System.out.println("");
}

edited Nov 09 '14 at 02:47

Mr. Polywhirl

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answered Nov 09 '14 at 02:46

vmontanheiro

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Array 2D looping

1 Answers1