Is it possible to call a method by its name as string?
#define callmethod(function) \
this->#function();
Just a simple example. (it doesn't work).
callmethod("myfunction");
error: expected unqualified-id before string constant
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yayuj
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2the short answer: no. the long answer: it can be done by reflection in java/c#. i don't know about c++ so i don't post an answer – No Idea For Name Nov 11 '14 at 13:26
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2The `#` preprocessor operator is the *stringify* operator, i.e. it converts the arguments symbol *to* a string, not the other way around. – Some programmer dude Nov 11 '14 at 13:26
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2And no, it's can't generally be done in C++. You *can* make a `std::map` which maps strings to (e.g.) [`std::function`](http://en.cppreference.com/w/cpp/utility/functional/function) objects. – Some programmer dude Nov 11 '14 at 13:27
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Not sure - never tried or saw anything (not yet). – ha9u63a7 Nov 11 '14 at 13:27
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1You need to make a map with function names and pointers. – Alex F Nov 11 '14 at 13:27
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Maybe you could cook something up with the preprocessor stringify operator mentioned above, and dlopen()/dlsym(), at least on Linux. Look at 'man dlsym'. – Erik Alapää Nov 11 '14 at 14:16