print highest value in dict with key

Question

My dict is like,

{'A':4,'B':10,'C':0,'D':87}

I want to find max value with its key and min value with its key.

Output will be like ,

max : 87 , key is D

min : 0 , key is C

I know how to get min and max values from dict. Is there is any way to get value and key in one statement?

max([i for i in dic.values()]) 
min([i for i in dic.values()])

Use a lambda expression – Mr. Polywhirl Nov 11 '14 at 18:30 — Mr. Polywhirl, Nov 11 '14 at 18:30
What about duplicate values? Do you want both/all keys? – Árni St. Steinunnarson Nov 11 '14 at 18:32 — Árni St. Steinunnarson, Nov 11 '14 at 18:32

score 58 · Accepted Answer · answered Nov 11 '14 at 18:32

58

You could use use max and min with dict.get:

maximum = max(mydict, key=mydict.get)  # Just use 'min' instead of 'max' for minimum.
print(maximum, mydict[maximum])
# D 87

answered Nov 11 '14 at 18:32

anon582847382

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i dont think it will work, – Hackaholic Nov 11 '14 at 18:36
1

@hackaholic Do explain why, I'd love to know. – anon582847382 Nov 11 '14 at 18:36
1

what if D has lowe value than A and C – Hackaholic Nov 11 '14 at 18:36
@Hackaholic Then that value wouldn't be returned... the whole point is to return the keys with the highest and lowest value. – anon582847382 Nov 11 '14 at 18:37
8

You could also do `key, value = max(mydict.iteritems(), key = lambda p: p[1])`, since the question specifically mentions getting the key and value together. But it's rarely worth typing more code just to save dictionary lookups. – Steve Jessop Nov 11 '14 at 18:53
1

Make sure your values are numbers and not strings or you will get wrong answers. – Noumenon May 08 '17 at 21:41

holdenweb · Answer 2 · 2019-02-05T16:01:48.027

14

The clue is to work with the dict's items (i.e. key-value pair tuples). Then by using the second element of the item as the max key (as opposed to the dict key) you can easily extract the highest value and its associated key.

 mydict = {'A':4,'B':10,'C':0,'D':87}
>>> max(mydict.items(), key=lambda k: k[1])
('D', 87)
>>> min(mydict.items(), key=lambda k: k[1])
('C', 0)

edited Feb 05 '19 at 16:01

answered Nov 11 '14 at 19:05

holdenweb

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Hackaholic · Answer 3 · 2020-12-11T21:34:44.240

6

just :

 mydict = {'A':4,'B':10,'C':0,'D':87}
 max(mydict.items(), key=lambda x: x[1])

edited Dec 11 '20 at 21:34

answered Nov 11 '14 at 18:30

Hackaholic

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5

This doesn't meet the specifications of the question. It is supposed to find the key with the highest value; not the greatest key and the greatest value. – anon582847382 Nov 11 '14 at 18:39

print highest value in dict with key

3 Answers3

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