Unknown Syntax void (Type::m_function)()

Question

I am currently reading through some code and came across a few lines I do not understand.

First

void Foo()
{
    (((Type*)parent)->*m_function)();
}

As far as I can tell they are casting the parent to Type and then calling a dereferenced function? I am not sure I have seen the ->*m_function before.

Also I can not see where m_function is declared perhaps here? Which contains more syntax I do not understand. Is it declaring a function that returns void and takes a parameter of a function? But where is the function name?

class Foo()
{
    void (Type::*m_function)();
};

score 2 · Accepted Answer · edited May 23 '17 at 12:12

2

It's calling a member function using a pointer to this function: C++ Call Pointer To Member Function

Yes, void (Type::*m_function)(); declares m_function member of type "member function of Type taking 0 args and returning void"

edited May 23 '17 at 12:12

Community

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answered Nov 14 '14 at 18:41

Andriy Tylychko

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Unknown Syntax void (Type::m_function)()

1 Answers1