I'm wondring if there is any way to create new variables from the name of the currently inspected item in a for loop:
list = ["a", "b", "c"]
for item in list:
item_new = 1
print a_new
print b_new
print c_new
What i want this to outputis:
1
1
1
Edit: Ouch, ok, point taken :P
Knew a dict would work in this instance, just wanted to check if the method above was viable. Apparently not!
You should not do this with variables. A dictionary is what you are looking for:
list = ["a", "b", "c"]
variables = {}
for item in list:
variables[item] = 1
print variables["a"]
print variables["b"]
print variables["c"]
The locals() function returns a reference to a dict where you can inspect local variables, and each key represents the local variable name as an string:
>>> locals()
{'a': 2, 'b': 9, '__builtins__': <module '__builtin__' (built-in)>, '__package__': None, '__name__': '__main__', '__doc__': None}
>>> var = "Some text"
>>> locals()
{'var': 'Some text', 'a': 2, 'b': 9, '__builtins__': <module '__builtin__' (built-in)>, '__package__': None, '__name__': '__main__', '__doc__': None}
There is also the globals() function that you can also use not only to inspect global variables but also to create new global variables dynamically:
>>> globals()['ZZ'] = 123
>>> ZZ
123
But please, don't do this. This program is unmainteinable. Use a normal dict to create custom elements with your code. This program is way far more readable and maintainable:
list = ["a", "b", "c"]
d = {}
for item in list:
d[item] = 1
print d['a']
print d['b']
print d['c']
Instead of creating new variables, a dictionary seems like a better approach.
Also, it's best to not use the variable name list, because that is already the name of a function.
L = ["a", "b", "c"]
d = {}
for item in L:
d["{}_new".format(item)] = 1
print d["a_new"]
print d["b_new"]
print d["c_new"]
