File name pattern matching in unix shell script

Question

cd /DIR1/

if [ -f  abc_*] ; then

ls -l abc_*| awk 'NR >0 && !/^d/ {print $NF}' >>list.txt

chmod 664 list.txt

else

echo "file not found"

fi

it giving the error as "Binary Operator expected "

If any files found in the directory starting with the pattern "abc_" it should create a file called list.txt and move the filenames to list.txt

possible duplicate: http://stackoverflow.com/questions/24603037/binary-operator-expected-error-when-checking-if-a-file-with-full-pathname-exists or http://stackoverflow.com/questions/8340144/please-help-me-binary-operator-expected-in-cygwin — jaynp, Nov 20 '14 at 07:52

score 0 · Answer 1 · answered Nov 20 '14 at 07:53

0

-f checks for the existance of a single file, you can rather use

if ls abc_* 2>/dev/null; then 
  do stuff
fi

answered Nov 20 '14 at 07:53

Decado

hi thanks for your reply.. Can you explain what is the meaning of ls abc_* 2>/dev/null – RonuRaj Nov 20 '14 at 07:56
You should not parse output of ls command.. – SMA Nov 20 '14 at 07:59
Hi Please give me the exact command – RonuRaj Nov 20 '14 at 08:03

score 0 · Answer 2 · edited Nov 20 '14 at 08:12

0

You could just use single liner find command like below:

find . -maxdepth 1 -name "abc_*" -printf "%f\n" >> list.txt

find command will find your files in current (replace . with /DIR1 to find in /DIR1) directory

maxdepth - just in directory specified and not recursively within each directories.
name name like abc_*
printf - print just the file name without directory prefixed.

edited Nov 20 '14 at 08:12

answered Nov 20 '14 at 08:03

SMA

2 Answers2