Uint16Array to Uint8Array

Question

I have a basic question. Say I have a Uint16Array and I have number 4 in it.

data_16=new Uint16Array([4]);

Now I have a length 1 and byteLength 2;

how do i convert this to Uint8Array.

I do not want to create a new view.

data_8 = new Uint8Array(data_16)

If I do this I get array length 1 and byteLength 1. This is not what I want.

I need to stretch that 16 bit value in 16array into 8 bit values so that 8bit array so it would end up with 2 values int 8 bit array.

I can just create a funtion which converts with shif and to all that stuff. But Can it be done with Array manipulation only?

score 16 · Accepted Answer · edited Jan 18 '20 at 15:04

16

You can use the buffer property, i.e. data_8 = new Uint8Array(data_16.buffer, data_16.byteOffset, data_16.byteLength).

edited Jan 18 '20 at 15:04

qntm

answered Feb 03 '15 at 04:33

Steve Campbell

2

I suggest `new Uint8Array(data_16.buffer, data_16.byteOffset, data_16.byteLength)`, because in the general case there's no guarantee that `data_16` views all of its backing `ArrayBuffer`. – qntm Jan 13 '20 at 23:12

score 0 · Answer 2 · answered Dec 26 '22 at 01:45

0

Would like to note that the current accepted answer may not work because of the byte order is platform dependent.

answered Dec 26 '22 at 01:45

Hunts Chen

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2 Answers2