how to json_encode 'php array'

Question

i have the following array like this :

{"label":"label1","data":[[10,55],[15,32],[16,49]]}
{"label":"label","data":[[10,55],[15,32],[16,49]]}

how to get string character (,) beetween {"label":"label1","data":[[10,55],[15,32],[16,49]]} and {"label":"label2","data":[[10,55],[15,32],[16,49]]} result like this..

{"label":"label1","data":[[10,55],[15,32],[16,49]]},
{"label":"label","data":[[10,55],[15,32],[16,49]]}

Code

while($row = mysql_fetch_assoc($result))
{   
    $int = $row['SC'];
    $join = intval($int);
    $int2 = $row['jam'];
    $join2 = intval($int2);
    $dataset1[] = array($join2,$join);

}
for ($i=0; $i <2 ; $i++) { 
$dataset = array(label => label1, data => $dataset1);
$final = json_encode($dataset);

echo $final;

Using mysql_fetch_assoc! Then read [this](http://stackoverflow.com/questions/12859942/why-shouldnt-i-use-mysql-functions-in-php). — Nabil Kadimi, Nov 21 '14 at 02:08
but really, using `mysqli_...`, because `msql_...` has been removed from PHP. — Mike 'Pomax' Kamermans, Nov 21 '14 at 02:09
Sure you don't mean `$dataset1[$i]` in that for loop? Or are you seriously dumping the same thing over and over? — Brad Christie, Nov 21 '14 at 02:11
This code only produces one {label....} object. How you would join two or more of them depends on how you generate the others. — James, Nov 21 '14 at 02:14
What is `$label = label` doing? Should that be `$label[] = $row['label']`? — Barmar, Nov 21 '14 at 02:16
@BradChristie yes i'm seriously dumping the same thing over and over — Yovhi, Nov 21 '14 at 02:18

score 3 · Accepted Answer · answered Nov 21 '14 at 02:18

You need to put everything into another array:

$dataset = array();
foreach ($dataset1 as $d) {
    $dataset[] = array('label' => $label, 'data' => $d);
}
$final = json_encode($dataset);
echo $final;

This should output:

[{"label":"label1","data":[[10,55],[15,32],[16,49]]},
 {"label":"label","data":[[10,55],[15,32],[16,49]]}]

how to json_encode 'php array'

1 Answers1