i want a Base
template class with 2 template parameters. Specially, second parameter is a template parameter. Derived
is derived from Base
with CRTP. Now i want to generate the base class of Derived
like Base<Derived,Derived::second_tmpl>
, but the generating base class isn't same as the real base class of Derived
. How do i transmit a template?
#include <type_traits>
template<typename T, template<typename>class U>
struct Base
{
using type = Base<T,U>;
using devired_type = T;
template<typename V>
using second_tmpl = U<V>;
using second_type = second_tmpl<type>;
};
template<typename T>
struct Template
{
using type = Template<T>;
};
struct Derived
:public Base<Derived,Template>
{
};
//true
static_assert(
std::is_same<
Derived::second_type,
Template<Base<Derived,Template>>>::value,
"false");
//false
static_assert(
std::is_base_of<
Base<Derived,Derived::second_tmpl>,
Derived
>::value,
"false");
template<typename T>
using Template2 = Template<T>;
//false
static_assert(
std::is_same<
Base<Derived,Template>,
Base<Derived,Template2>
>::value,
"false");
Use a template which is the same as the original template instead of the original template. The judgement is false;