How to find the array size?

Question

Here is my simple code in c++..

int getSize(int *array){
int n = (sizeof(array)/sizeof(array[0]));
return n;

}

int main(){
    int array[4] ={1,2,3,4};
    std::cout<< getSize(array)<<std::endl; // prints 2 (first 2 elements)
}

I am a newbie in C++. I am not able to figure out the issue.

sizeof(array) returns the size of a pointer – Min Fu Nov 26 '14 at 08:05 — Min Fu, Nov 26 '14 at 08:05

score 2 · Accepted Answer · answered Nov 26 '14 at 08:05

2

That should be:

template <std::size_t N>
std::size_t getSize(const int (&)[N]){ return N; }

answered Nov 26 '14 at 08:05

Jarod42

2

From the OP: "I am a newbie in C++." I.e. doesn't know templates or lambdas. If you're going to use advanced techniques, at least explain them to some degree. – David Nov 26 '14 at 08:09

1 Answers1