zip a file in python

Question

I'm trying to zip a file in python, my code is:

import zipfile
f = zipfile.ZipFile('/home/tom/Desktop/test.csv.zip','w',zipfile.ZIP_DEFLATED)
f.write('/home/tom/Desktop/test.csv')
f.close()

It's working well, but inside my zip file I'm having the full path: /home/tom/Desktop/test.csv

How can I just get test.csv inside the zip file?

Does this answer your question? [How to create a zip archive of a directory in Python?](https://stackoverflow.com/questions/1855095/how-to-create-a-zip-archive-of-a-directory-in-python) — Omega Krypton, Jan 29 '20 at 14:28

score 2 · Accepted Answer · edited Jun 20 '20 at 09:12

2

From docs:

ZipFile.write(filename[, arcname[, compress_type]])

Write the file named filename to the archive, giving it the archive name arcname (by default, this will be the same as filename, but without a drive letter and with leading path separators removed).

So...

f.write('/home/tom/Desktop/test.csv', 'test.csv')

edited Jun 20 '20 at 09:12

Community

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answered Dec 01 '14 at 04:29

Amadan

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zip a file in python

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