passing PHP var to JS var

Question

I have a small issue. I can't seam to pass a variable from PHP to JS.

Here is my JS:

var eName = '<?php echo $eName; ?>';

I know that $eName has a value. However in the JS section, I get nothing. no data seams to be present in the variable. when I echo in the PHP section, I get data.

Can anyone help?

Also tried:

var eName = '<?php echo json_encode($eName); ?>';

This give me a null result

Thanks for your help

Here is how I get my PHP Variable populated:

$sql="SELECT * FROM league WHERE id='". $lID ."' LIMIT 1";
    $result = mysqli_query($db_conx, $sql);
    $numrows = mysqli_num_rows($result);
    if($numrows < 1){
        echo "league does not exist";
        exit();
    }
    while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
        $eName = $row["name"];

Sounds like a scoping issue in PHP. Are you sure the variable is defined in the global PHP scope? — Sirko, Dec 01 '14 at 16:44
Works fine for me! Also should work for you! Please show us more code — Rizier123, Dec 01 '14 at 16:44
$eName is not an array. I get a single name from my database. such as: "VIP", "8 Ball". Not sure I understand the global PHP scope question, I'll read on it. — Richard Moreau, Dec 01 '14 at 16:45
Actually, it should be just `var eName = ;`, without any quotes; that's the safest way, unless `$eName` contains non-serializable data. Could you show what's put in the source code as a result? — raina77ow, Dec 01 '14 at 16:45
You are pushing the PHP code in the JS File. JS cannot interpret the php code. You need to use JS ajax to load the data as a web service ot some other way around — Akhilesh Sharma, Dec 01 '14 at 16:47
Raina77ow, I tried it already. The alert returns a NULL value. — Richard Moreau, Dec 01 '14 at 16:48
I didn't mention any alert, did I? Check the source code directly. If it contains something like `var eName = null`, it means that `$eName` variable doesn't have any value when you echo it, for whatever reason there is - typo, scope issues etc. — raina77ow, Dec 01 '14 at 16:49
I am using ajax. If I echo in PHP I see the value in my ajax.responseText — Richard Moreau, Dec 01 '14 at 16:50
And the PHP response is what exactly? I don't understand how an Ajax response is related to `var eName = '';`. Please **[edit]** your question and provide more (complete) information. — Felix Kling, Dec 01 '14 at 16:52
I just used the ajax response to make sure the variable was not empty in my php section. I tried to make the variables global, same thing. — Richard Moreau, Dec 01 '14 at 16:58
Can you show the code that assigns a value to this variable? Is that code before or after section with JS (i.e., `var eName = ...`)? — raina77ow, Dec 01 '14 at 17:06
I read and followed the instruction in this post: down vote favorite This question may already have an answer here: How to pass variables and data from PHP to JavaScript? This is how I got the code i'm using. Still it is still not working. This is why I am asking for help. — Richard Moreau, Dec 01 '14 at 17:09

Sithu · Answer 1 · 2014-12-01T17:20:43.403

0

According to your edited code, I guess your variable $eName would be empty for the last record of the while loop.

while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
    $eName = $row["name"];
    // if the last record has the empty value for the field `name`, 
    // it will overwrite the previous value and
    // you will get `$eName` of no value out of the loop later
}

And moreover, make sure you are not using <?php ?> in the .js file which is not parsed by Javascript.

edited Dec 01 '14 at 17:20

answered Dec 01 '14 at 17:12

Sithu

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It is not, I get the right value after the While. – Richard Moreau Dec 01 '14 at 17:15

passing PHP var to JS var

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