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I'm receiving intents sent with default share mechanism (ACTION_SEND) from different applications.

If it is a file – I need to copy it.
I don't need a full path to file since I can open it directly with a stream.

InputStream input = getContentResolver().openInputStream(fileUri);

But I need to know a filename to save file properly.

Is there any easy and universal way to get a filename of the shared file not paying attention to the content type (it can be image from gallery, video, files from downloads)?

Or should I use something like this to get the full path from the uri and then get filename from it?

Get real path from URI, Android KitKat new storage access framework [duplicate]
Android Gallery on KitKat returns different Uri for Intent.ACTION_GET_CONTENT

Also I saw this article (A Uri Is Not (Necessarily) a File) and there is said:

You can perform the following operations on such Uri values:

  • Find out their DISPLAY_NAME and SIZE — the OpenableColumns — via a query() on the Uri (again, using a ContentResolver, or in theory a CursorLoader)

Is it possible? How can I do that?

Community
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nicolausYes
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1 Answers1

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According to the MediaStore interface the DISPLAY_NAME column is indeed delivered.

Cursor cursor = getContentResolver().query(fileUri, projection, null, null, null);

projection contains DISPLAY_NAME

cursor.moveToFirst();
if (cursor.getCount() > 0) {
    // get your file name
}

I have not tested it but it should work ;-)

Carsten
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