Shorthand way to initialise a 2D/3D array in C?

Question

I was wondering if there is a shorthand way to initialise a 2D or 3D array in C similar to the following syntax:

int array[1024] = {[0 ... 1023] = 5};

You apparently left out the "1D" in your title, which is what your posted code actually is. Not sure what the "D" has to do with your question, come to think of it. — WhozCraig, Dec 05 '14 at 11:06
That's a [GCC extension](https://gcc.gnu.org/onlinedocs/gcc/Designated-Inits.html), it's not standard C. — unwind, Dec 05 '14 at 11:13
@WhozCraig I was asking if there was a way to init multidimensional arrays using the '[first ... last] = value' syntax - the code I posted was just an example of using this syntax with a standard array. Thanks all for correcting my mistake though. — Liam Lacey, Dec 05 '14 at 11:45
Not exactly a duplicate but answers the question: http://stackoverflow.com/questions/21528288/c-structure-array-initializing — Lundin, Dec 05 '14 at 12:18

score 5 · Accepted Answer · answered Dec 05 '14 at 11:14

5

The initialization you use isn't standard C, it's a GCC extension (Designated Initializers).

To initialize a 3d array, use:

int array[10][10][10] = {[0 ... 9] [0 ... 9] [0 ... 9] = 42};

answered Dec 05 '14 at 11:14

Yu Hao

1 Answers1