PHP URL Error Handing

Question

I'm trying to find a way to handle any 4xx and 5xx error status codes throw by a url like Apache 404 error. I'd like to execute the contents of the if statement only if there are no error status codes thrown by the server.

Using the following if statement it seems that even with the hosted content not being found and throwing an Apache 404 error its still running the contents of the if statement.

if (@fopen('http://example','r')){
            use resource
}
else{
use other resources
}

is there a better way to ensure the url is available before running it?

Edit: i can't use curl in this instance.

thanks

There are no such things as errors, there are only status codes that required url returns. — Yang, Dec 06 '14 at 03:47
I can't use curl, i wish i could. I was under the impression that 4xx and 5xx status codes where called Error status codes. Sorry i should of been more clear. — bakingsoda, Dec 06 '14 at 03:53
Check the [answer](http://stackoverflow.com/a/408420/3049065) which is related to your expectation. — Mahendran Sakkarai, Dec 06 '14 at 12:27

Sanjeev Hegde · Answer 1 · 2014-12-06T05:34:22.227

0

Use this.

  $headers = @get_headers($url, 1);
  if ($headers[0] == 'HTTP/1.1 200 OK') {
  //valid 
  }
   if($headers[0] == 'HTTP/1.1 404 Not Found') {
    // not found
   }   
  if ($headers[0] == 'HTTP/1.1 301 Moved Permanently') {
  //moved or redirect page
  }

get_headers() manual:http://php.net/manual/en/function.get-headers.php

edited Dec 06 '14 at 05:34

answered Dec 06 '14 at 05:09

Sanjeev Hegde

168
9

score 0 · Accepted Answer · answered Dec 06 '14 at 05:35

0

 $headers = get_headers($url, 1);
  if ($headers[0] == 'HTTP/1.1 200 OK') {//no error status codes thrown by the server
   $data = file_get_contents($url);
   //Do something
  }

answered Dec 06 '14 at 05:35

4EACH

2,132
4
20
28

PHP URL Error Handing

2 Answers2