How to pass argument to java bash script?

Question

I have a simple bash script which runs my java program. Here is it:

run.sh

#!/bin/sh
java -jar target/my-jar-arch.jar

I want to pass arguments to this script, which must pass them to java program:

bash run.sh myArg -key 100

When I try to execute this line my app doesn't get any parameters. How can I fix it?

`java -jar target/my-jar-arch.jar "$@"` – Dima Dec 07 '14 at 15:29 — Dima, Dec 07 '14 at 15:29

score 6 · Accepted Answer · answered Dec 07 '14 at 15:29

6

Change your invocation line to:

java -jar target/my-jar-arch.jar "$@"

answered Dec 07 '14 at 15:29

fge

Oh maybe you know how to make my script executable? If I run it `run myArg -p 100` I get `-bash: run: command not found`. Seams the problem is in my env. – Aaron Dec 07 '14 at 16:07
It should be `./run.sh`. Unix systems won't automagically "append extensions" or whatever; in fact they don't have the notion of an extension at all. – fge Dec 07 '14 at 16:12
The problem isn't in extension. It is in my .bash_profile I think. – Aaron Dec 07 '14 at 16:12
is there any possibility to pass few bash variables in to the java -jar command? Eg:- java -jar org.sample.jar $HOST $PORT assume I already have HOST and PORT defined within my bash script. – udarakr Apr 02 '16 at 22:16

1 Answers1