How to write these commands to Serial Port?

Question

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In the above table there is a command "CLR" with Description(hex) "OC"

When I write that command to serial port I write "port.Write(new byte[]{ 0x0C } ) " and that works.

But I don't really understand how to write other commands in this list to serial port for example ESC DC1 command , ESC Q A...........CR command

Can someone please give me a bit of a explanation about these Code descriptions ? and how should I format them when I write to serial port ?

Please help me, I appreciate your help very much. :) Please be so kind enough to help me.

Can you please help me ? , or please tell me a keyword which I should google for ? — Real Programmer, Dec 07 '14 at 20:01
As your doc says `ESC=0x1B` and `DC1=0x11`, So similar to your port.Write — L.B, Dec 07 '14 at 20:04
Do just what you did for CLR, but include the additional values, separated by commas. See the answer to this question to see how to initialize a byte array http://stackoverflow.com/questions/6150097/initialize-a-byte-array-to-a-certain-value-other-than-the-default-null — hatchet - done with SOverflow, Dec 07 '14 at 20:09

score 1 · Accepted Answer · edited Jun 20 '20 at 09:12

1

Have you tried just doing the same thing for the other commands as you did for the CLR command? E.g. for ESC DC1:

port.Write(new byte[]{ 0x1B, 0x11 } );

Or for your other command:

port.Write(new byte[]{ 0x1B, 0x51, 0x41 } );

//Then write the 20 bytes that you want in your line,and then...

port.Write(new byte[]{ 0xD } );

edited Jun 20 '20 at 09:12

Community

answered Dec 07 '14 at 20:08

Eugene Osovetsky

Oh , I was not sure how to write it when there are two pieaces in same command like "1B 11" – Real Programmer Dec 07 '14 at 20:10
Osvetsky, One more thing, Please tell me how to write this one "B 51 44 [n ]x20 0D " ? – Real Programmer Dec 07 '14 at 20:14
and what is that "[n ]x20 OD" in "B 51 44 [n ]x20 0D" ? if write "0XB , 0X51 , 0X44" then we are only writing "B 51 44" this, right ? – Real Programmer Dec 07 '14 at 20:19
You write 3 bytes (0x1B, 0x51, 0x41), then you write 20 more bytes that represent the line you want to display, then you write 1 more byte (0xD), so in total you write 24 bytes. – Eugene Osovetsky Dec 07 '14 at 20:23

1 Answers1