c++11 regex and '[' escape

Asked Dec 12 '14 at 16:05

Active Dec 12 '14 at 16:05

Viewed 23 times

My Problem

I have this problem i don't really understand: i wanted to create a std::basic_regex matching n+ '[' like this:

[...]
std::basic_regex("[+");
[...]

but well '[' has not be escaped, so i get this exception (which is logic):

terminate called after throwing an instance of 'std::regex_error'
  what():  regex_error

Then I tried to repair my mistake by escaping the '[' like this:

[...]
std::basic_regex("\\[+");
[...]

And there I don't know why but i still got the throwing exception:

terminate called after throwing an instance of 'std::regex_error'
  what():  regex_error

So?

Anyone has this same error? or am i doing something wrong?

Edit:

Forgot to put my g++ version:

g++ (Ubuntu 4.8.1-2ubuntu1~12.04) 4.8.1
Copyright (C) 2013 Free Software Foundation, Inc.
This is free software; see the source for copying conditions.  There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.

asked Dec 12 '14 at 16:05

CollioTV

1

try this `"[\\[]+"` . I think there no problem with your regex. – Avinash Raj Dec 12 '14 at 16:08
regex is only properly supported in gcc 4.9+ – nhahtdh Dec 12 '14 at 16:09
@AvinashRaj You my friend is the best (can you just post a answer in order to validate it?) – CollioTV Dec 12 '14 at 16:09
@nhahtdh i take not on this! – CollioTV Dec 12 '14 at 16:09

c++11 regex and '[' escape

My Problem

So?

Edit:

0 Answers0