Reading from a file Haskell

Question

Read from file those lines and make a list like this

 2010‐04‐16,130.68,132.17,130.25,130.63,9546200,130.63
 2010‐04‐15,130.53,131.14,130.19,130.89,6425300,130.89   

List [ "2010‐04‐16","130.68,132.17","130.25","130.63","9546200","130.63"]

how i can make this with take predicate ? or any other predicates

@user760157 Did you look at my answer? Was it helpful or do you need more clarification? — bmk, Dec 14 '14 at 16:27

bmk · Accepted Answer · 2014-12-14T15:45:18.560

0

I could do something like this using Data.List API:

import Data.List

split :: Eq a => a -> [a] -> [[a]]
split delim = map (dropWhile (== delim)) . groupBy (\_ c -> c /= delim)

The output with one of your input strings will be:

Prelude Data.List> split ',' "20100416,130.68,132.17,130.25,130.63,9546200,130.63"
["20100416","130.68","132.17","130.25","130.63","9546200","130.63"]

HTH...

edited Dec 14 '14 at 15:45

answered Dec 14 '14 at 14:43

bmk

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You meant `split :: Eq a => a -> [a] -> [[a]]`, right? – Shoe Dec 14 '14 at 15:20

Reading from a file Haskell

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